WebApr 27, 2024 · answered. ANSWER FAST PLEASE. P (B) = 2/3. P (A ∩ B) = 1/6. What will P (A) have to be for A and B to be independent? 1/2. 1/4. 11/12. 5/6. WebFirst, you should prove for any sets A and B that ( A ∪ B) c = A c ∩ B c. This is one of DeMorgan's laws. It's easy to prove, so try it. If you have trouble, let me know. Then notice …
Calculating conditional probability (video) Khan Academy
WebGive examples to show that both extremes for p (A ∪ B) are possible. probability Suppose that P (A)=.4 and P (B)=.2. If events A and B are independent, find these probabilities: a. P … Web1.3.6 Solved Problems: Random Experiments and Probabilities. Problem. Consider a sample space S and three events A, B, and C. For each of the following events draw a Venn diagram representation as well as a set expression. Among A, B, and C, only A occurs. At least one of the events A, B, or C occurs. A or C occurs, but not B. sims 4 greek mythology cc
SOLUTION: Let A and B be events with P(A)=1/2, P(B)=1/3 …
WebThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer. Question: Suppose events A, B, and C are independent and P (A) = 1/2 P (B) = 1/3 P (C) = 1/4 Find the probability . (Enter the probability as a fraction .) P [ (AuB)’n C] WebP(A and B) = P(A) x P(B A) Here is how to do it for the "Sam, Yes" branch: (When we take the 0.6 chance of Sam being coach times the 0.5 chance that Sam will let you be Goalkeeper we end up with an 0.3 chance.) But we are not done yet! We haven't included Alex as Coach: An 0.4 chance of Alex as Coach, followed by an 0.3 chance gives 0.12 WebFeb 19, 2024 · If A, B and C are independent events, P(A ∩ B) = 1/2, P(B ∩ C) = 1/3, P(C ∩ A) = 1/6, then find P(A), P(B) and P(C). asked Feb 19, 2024 in Probability by Architakumari (44.1k points) probability; class-11; 0 votes. 1 answer. For two events A and B of a sample space S, if P(A ∪ B) = 5/6, P(A ∩ B) = 1/3, then find P(A). sims 4 greenfield grocery store + cc