WebFirstly, you have to find the constant of k by using the discriminant. = (4k) 2 – (4 x 1 x (3+11k)) = 16k 2 – 44k – 12 Then use the quadratic formula to find the two values of k. For ease, I find the two values of k as 3 and-0.25. Secondly, replace your values of k into the original function which should give you a simpler quadratic equation. Then you will be … Webfx=x2+4kx+3+11k , where k is a constant. Given mar equation fx=0 has no real root find the ser or porrible values or k.
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Web0:00 / 2:45 Complete the square to find the vertex: f (x)=-2x^2+8x+3 Mark Dwyer 3.99K subscribers Subscribe 2.2K views 8 years ago Completing the Square This video … WebCompleting the square, f(x) = (x + 2k)^(2)-4k^2 + 3 + 11k So p should be 2k and q,-4k^2 + 3 + 11k. A little tip for you to check is to put specific values into x and k and check if they … biovitt whey
1. fx=x2+4kx+3+11k ,where k is a constant. a Expre - Gauthmath
WebMar 5, 2015 · the question is : By considering the discriminant, or otherwise, find the range of values of 'k' that gives the equation 2 distinct roots. 3 x 2 + k x + 2 = 0 this is what i have done so far: b 2 − 4 a c > 0 Note - since there are two distinct real roots k 2 − 24 > 0 considering k 2 − 24 = 0 k = + − 24 k = 2 ∗ 6 or k = − 2 ∗ 6 WebGold 3: 11/12 6 10. Figure 2 Figure 2 shows a sketch of the curve H with equation y = x 3 + 4 , x 0. (a) Give the coordinates of the point where H crosses the x-axis.(1) (b) Give the equations of the asymptotes to H.(2) (c) Find an equation for the normal to H at the point P(–3, 3).(5) This normal crosses the x-axis at A and the y-axis at B. (d) Find the length of … WebJun 2, 2012 · Finding the value of k if a line y = 2x +k is a tangent to a circle x^2 +y^2 -10x = 0 mattam66 6.3K subscribers Subscribe 107 20K views 10 years ago In this video I have explained... dale heitland obituary