WebDec 9, 2024 · 1 Answer Sorted by: -1 You should never store date/time values as strings, use proper Date object. Convert the string to Date, then you can extract monthDayYear: { $dateToString: { format: "%m/%d/%Y", date: { $dateFromString: { dateString: "$conDate", format: "%Y-%m-%d %H:%M:%S"} } } }, Mongo Playground Share Improve this answer … WebNov 12, 2024 · Getting an error, 'Can't convert from BSON type objectId to String' when using MongoDB aggregation Ask Question Asked 3 years, 4 months ago Modified 3 years, 4 months ago Viewed 620 times 0 I am trying to get the last message of every single conversation between User 1 and User N.
java - Creating BSON object from JSON string - Stack Overflow
WebThe System.FormatException with the message " XXX is not a valid 24 digit hex string" is typically thrown by the MongoDB driver's ObjectId.Parse method when the specified string is not a valid ObjectID value. ObjectIDs are unique identifiers used in MongoDB documents, and are represented as a 24-digit hexadecimal string. WebTo import a .bson file, run the following command on your system command line. mongorestore -d db_name /path/file.bson. Here, db_name is the name of the database you want to import. Path denotes the absolute path of your .bson file, while file represents the BSON file’s name. dynamics user license type
Exception: can
WebBSON strings are UTF-8. In general, drivers for each programming language convert from the language's string format to UTF-8 when serializing and deserializing BSON. This makes it possible to store most international characters in BSON strings with ease. [ 1] In addition, MongoDB $regex queries support UTF-8 in the regex string. [ 1] WebApr 10, 2015 · Here your string "8001_469437317594492928_1400737805000" is not 12 byte BSON type. so update according to ObjectId. To generate a new ObjectId using the ObjectId () constructor with a unique hexadecimal string: var stringObjectId = ObjectId ("507f191e810c19729de860ea"); Please make string correct to convert string to objectId. WebNov 23, 2010 · problem is that your converting string s2 to string again and store it in DateTime variable Try this: DateTime dt = Convert.ToDateTime ("11/23/2010"); string s2 = dt.ToString ("dd-MM-yyyy"); DateTime dtnew = Convert.ToDateTime (s2); Share Improve this answer Follow edited Dec 21, 2010 at 10:30 abatishchev 97.3k 85 297 432 dynamics user group 2022